Givens: 12 inch = 1 feet.

Style (A) dimensions = 12 x12 x 12. •Package cost 60 cent. •Package weight 1 pound. •Style (A) Shade cost $ 4. •Style (A) Shade weight 10 pounds. Total Package + Shade (A) cost = $ 4 + 60 cents = $ 4.

6. Total Package + Shade (A) weight = 1 + 10 = 11 pounds. Total Package + Shade (A) volume = 1728 inch3 = 1 foot3 Container dimensions: 8 x 8. 5 x 40 = 2720 ft3 Maximum container weight = 44000 Container price = $ 1000 Shade (B) Package style (B) Shade dimensions = 12 x12 x 48. Package style (B) Shade cost = $ 2. Style (B) Shade cost = $ 5.

No. of Shades (B) ?Package = 6 Package total cost = 6 x 5 + 2 = $ 32 Package total weight = 62 pounds Package total volume = 6912 inch3 = 4 ft3 Shade (C) Package style (C) Shade dimensions = 12 x12 x 50. Package style (C) Shade cost = $ 3 Style (C) Shade cost = $ 6 No. of Shades (C) ? Package = 10 Package total cost = 10 x 6 + 3 = $ 63 Package total weight = 101 pounds Package total volume = 7200 inch3 = 4.

17 ft3 Question1: How many style A shades can be loaded into an intermodal container? The volume of the container ? the volume of one package = 2720 ? 1 = 2720 package Style (A) Shade.Package contains 1 shade = 2720 Style (A) Shade. Total weight = 2720 x 11 p = 29920 < 44000 (total weight of container). Question 2: How many style B shades can be loaded into an intermodal container? The volume of the container ? the volume of one package = 2720 ? 4 = 680 package Style (B) Shade. Package contains 6 = total shades 680 x 6 = 4080 Style (B) Shade.

Total weight = 680 x 62 p = 42160 < 44000 (total weight of container). Question 3: How many style C shades can be loaded into an intermodal container? The volume of the container ? the volume of one package = 2720 ? 4. 17 = 652. 7 approximately 652 package Style (B) Shade. Total weight = 652 x 101 p = 65852 > 44000 (total weight of container).

Maximum no. can fit in the container = 44000 ? 101 = 435. 6 = 435 packages. Package contains 10.

Total no of Shades in container = 435 x 10 = 4350 Style (C) Shade. Question 4: What are the total costs of delivering the style A shades to the port of importation? Total cost for delivering Style (A) Shade $5400 land rate. = no. of containers x cost of container= $1000 x 2 = $2000 [1] = total cost of Style (A) Shades = 5400 x 4. 6 = 24840 [2] Total of Style (A) Shades = 5400 ft3Total weight of Style (A) Shades = 5400 x 10 = 54000 p = 54000 ? 2000 = 27 ton. Total cost of ocean rate = 27 x 22 = $594.

Check Volume Every 40 ft3 = 1 ton. 5400 ? 40 = 130 ton. 135 x 22 = $ 2970 [3] Total cost of shipping Style (A) Shades= [1] + [2] + [3] = 2000 + 24840 + 2970 = $29810 Question 5: What are the total costs of delivering the style B shades to the port of importation? Total cost for delivering Style (B) Shade. = no.

of containers x cost of container= $1000 x 2 = $2000 [1] = total cost of Style (B) Shades = 5400 ? 6 = 900 (no. of packages) x $32 = 28800 [2] Ocean Rate:Total volume of Style (B) Shade = 4 x 900 = 3600 ft3. Total weight of Style (B) Shades = 900 x 62 = 55800 Total weight/ ton = 55800 ? 2000 = 27. 9 ~ 28 Total cost of ocean rates = 28 x 22 = $ 616 Check Volume 3600 ? 40 = 90 ton. 90 x 22 = $ 1980 [3] Total cost of shipping Style (B) Shades= [1] + [2] + [3] = 2000 + 28800 + 1980 = $32780 Question 6: What are the total costs of delivering the style C shades to the port of importation? Total cost for delivering Style (C) Shade. = no.

of containers x cost of container= $1000 x 2 = $2000 [1] = total cost of Style (C) Shades = 5400 ? 0 = 540 (no. of packages) x $63 = 34020 [2] Ocean Rate: Total volume of Style (C) Shade = 4. 17 x 540 = 2251. 8 ~ 2252 ft3.

Total weight of Style (C) Shades = 540 x 101 = 54540 Total weight/ ton = 54540 ? 2000 = 27. 27 ~ 28 Total cost of ocean rates = 28 x 22 = $ 616 Check Volume 2252 ? 40 = 56. 3 ~ 57 ton. 57 x 22 = $ 1254 [3] Total cost of shipping Style (C) Shades= [1] + [2] + [3] = 2000 + 34020 + 1254 = $37274 Question 7: Which style would you recommend? Why? Style (A) Shade is the better one as it has the lowest cost of shipping $2970.